In triangle ABC AD is bisector. Angle ADC = 110 degrees, angle ACB = 33 degrees. Find angle ABC.

The sum of the inner angles of the triangle ADC is 180, then the angle CAD = 180 – ACD – ADC = 180 – 33 – 110 = 370.

Since AD is the bisector of the angle BAC, its value is equal to CAD * 2 = 37 * 2 = 74.

Then the angle ABC = 180 – 33 – 74 = 73.

Answer: The angle ABC is 73.



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