In triangle ABC, angle A = 45 degrees, angle B = 60 BC = 3√2. Find AC

Knowing the magnitude of the two angles A and C, we find the third angle B.

Angle B = 180 ° – (45 ° + 60 °) = 75 °.

Using the sine theorem formula, we find the side AC.

AC / Sin B = BC / Sin A;

AC = BC * Sin B / Sin A;

AC = 3√2 * Sin 75 ° / Sin 45 °;

Using the table of V. Bradis, we determine:

AC = 3 * 1.41 * 0.9659 / 0.7071 = 5.78 cm;

Answer: AC side = 5.78 cm.