In triangle ABC, angle A = 45 degrees, angle B = 60 degrees, BC = 3√2 … find AC?

According to the sine theorem, the sides of a triangle are proportional to the sines of the opposite angles. Therefore, we can write down the equality: ВС / sinA = AC / sinB. Knowing the degree measure of angles A and B, we can find the values of their sines:
A = 45, sinA = √2 / 2;
B = 60, sinB = √3 / 2.
AC = BC * sinB / sinA = (3√2) * (√3 / 2) / (√2 / 2) = 3√3.