In triangle ABC, angle A = 65 degrees, angle B = 45 degrees. The heights of the triangle AD and BE

In triangle ABC, angle A = 65 degrees, angle B = 45 degrees. The heights of the triangle AD and BE intersect at point O. Find the degree measure of the angle AOB.

Consider a triangle ABD, in which the angle BAD = 180 – (90 + 45) = 45 °
Consider a triangle ABE, in which the angle ABE = 180 – (90 + 65) = 25 °
Now consider the triangle AOB, in which the angle AOB = 180 – (25 + 45) = 110 °
Answer: The AOB angle is 110 °.



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