In triangle ABC, angle A = 72 degrees, it is 80%, and angle B is 20% of angle C.

In triangle ABC, angle A = 72 degrees, it is 80%, and angle B is 20% of angle C. How many degrees do angle B and angle C of triangle ABC contain?

First you need to determine the value of the angle C.

Since we know that angle A is equal to 80% of angle C, then its value will be:

72 ° 8 80% / 100% = 72 ° / 0.8 = 90 °.

Determine the value of the angle B.

Since this angle is 20% of the C angle, multiply 90 ° by the known percentage to determine it.

We get:

90 ° * 20% / 100% = 90 ° * 0.2 = 18 °.

Checking the solution to the problem.

The angles of any triangle add up to 180 °.

72 ° + 90 ° + 18 ° = 162 ° + 18 ° = 180 °.

Answer: Angle C = 90 °, angle B = 18 °.