In triangle ABC, angle A = 90, angle C is 70, AD is bisector. find the corners of the triangle BAD.

The angles of a triangle add up to 180 °.

In the triangle ABC we find the angle B.

180 ° – (90 ° + 70 °) = 180 ° – 160 ° = 20 °

The bisector of angle A divides this angle into two equal angles of 45 °.

In triangle BAD, angle B and angle A are known. Find angle D.

180 ° – (45 ° + 20 °) = 180 ° – 65 ° = 115 °.

Answer: the angles of the triangle BAD are A = 45 °, B = 20 °, D = 115 °.



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