In triangle ABC, angle A = 90 degrees, and angle C is 40 degrees greater than angle B. Find angle B and angle C.

Let the angle B be equal to “x” degrees. It is known that the angle C is 40 degrees greater than the angle B, so the angle C is equal to “x + 40” degrees.

By condition, it is specified that the angle A is equal to 90 degrees. Knowing that the sum of the angles of a triangle is 180 degrees, we will compose the equation:

x + x + 40 + 90 = 180;

2x + 130 = 180;

2x = 180 – 130;

2x = 50;

x = 50: 2;

x = 25 (degrees) angle B.

Find angle C:

x + 40 = 25 + 40 = 65 (degrees) angle B.