In triangle ABC, angle A = angle C = 45 degrees Prove that the median BD divides triangle ABC

In triangle ABC, angle A = angle C = 45 degrees Prove that the median BD divides triangle ABC into two equal triangles

Since, by condition, BAC = BCA = 45, then the triangle ABC is isosceles, AB = BC.

BD is the median of the triangle, then AD = CD.

Side ВD in triangles ABD and ВСD is common, then triangles ABD and ВСD are equal on three sides, which was required to be proved.



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