In triangle ABC, angle A is 2 times greater than angle C and 30 degrees greater than angle B. Find the angles of this triangle.

In triangle ABC:
Angle A is 2 times the angle C;
Angle A is 30 degrees greater than angle B.
Find all the corners of the triangle.
Decision:
Let x be angle C, then angle A = 2 * x.
Since angle A is 30 degrees greater than angle C, then angle B = 2 * x – 30.
The sum of all the angles of the triangle is 180.
Let’s make an equation and get:
2 * x + 2 * x – 30 + x = 180;
4 * x – 30 + x = 180;
5 * x – 30 = 180;
5 * x = 180 + 30;
5 * x = 210;
x = 210/5;
x = 200/5 + 10/5;
x = 40 + 2;
x = 42;
Means:
Angle C = 42 °;
Angle A = 2 * 42 ° = 84 °;
Angle B = 2 * 42 ° – 30 = 84 ° – 30 ° = 54 °.