In triangle ABC, angle A is 30 degrees, AC = BC. Find angle C.

AC = BC (according to the problem statement);

angle A = 30 ° => isosceles triangle and angle B = 30 °;

The three angles in a triangle add up to 180 degrees.

180 ° = angle A + angle B + angle C;

angle C = 180 ° – (angle A + angle B);

angle С = 180 ° – (30 ° + 30 °);

angle С = 180 ° – 60 °;

angle C = 120 °.

Answer: 120 °.



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