In triangle ABC, angle A is 40 degrees, outside angle at vertex B is 102 degrees. Find angle C.

Since the sum of the outer and inner angles is 180 °, the angle B is equal to:

180 ° – 102 = 78 °.

Since the sum of the angles of the triangle is also 180 °, we get:

∠C = 180 ° – ∠A – ∠B = 180 ° – 40 ° – 78 ° = 62 °.

Answer: the desired value of the angle C is 62 °.



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