In triangle ABC, angle A is 45 degrees, B is 60, and BC = 3√2-x. Find the AC.

Using the sine theorem (the sides of a triangle are proportional to the sines of the opposite angles), we get the expression:

AC / sin (B) = BC / sin (A);

AC = BC * sin (B) / sin (A) = 3√2 * sin (60 °) / sin (45 °) = 3√2 * √3 / 2 * 2 / √2 = 3 * √3 / 4 …

Answer: the desired side AC is 3 * √3 / 4.



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