In triangle ABC, angle A is 48 degrees, angle B is 44 degrees. AD, BE, CF- bisectors intersecting at point O.

In triangle ABC, angle A is 48 degrees, angle B is 44 degrees. AD, BE, CF- bisectors intersecting at point O. Find the angle AOF.

By condition, two angles are known in triangle ABC, we can find the third, angle C.
Angle C = 180 ° – (48 ° + 44 °) = 180 ° – 92 ° = 88 °.
Consider a triangle AFC, in which the angle A = 48 ° (by condition), the angle C = 88 ° / 2 = 44 ° (FC is the bisector) are known. We can find the angle F.
Angle F = 180 ° – (48 ° + 44 °) = 180 ° – 92 ° = 88 °.
Consider a triangle AFO, in which the angle A = 48 ° / 2 = 24 ° (AD is the bisector), the head F = 88 ° are known.
Find the corner AOF.
Angle AOF = 180 ° – (24 ° + 88 °) = 180 ° – 112 ° = 68 °.
Answer: The AOF is 68 °.