In triangle ABC, angle A is 50 degrees, and angle B is 12 times less than angle C. Find angles B and C.

The sum of all the angles of a triangle is 180 °.
Let’s solve the problem using the equation.
Let angle B be x, then angle C is 13x. Let’s compose and solve the equation:
50 + x + 12x = 180;
x + 12x = 180 – 50;
13x = 130;
x = 130: 13;
x = 10.
Angle B = 10 °.
Angle C = 10 ° × 12 = 120 °.
Answer: angle B = 10 °; angle C = 120 °.