In triangle ABC, angle A is 50 degrees and angle B is 35. CD-height. Find the corners of the ACD triangle.

Since, by condition, CD is the height of the ABC triangle, the ACD and BCD triangles are rectangular.

The sum of the acute angles of a right-angled triangle is 90, then in the ACD triangle the angle ACD = (90 – CAD) = (90 – 50) = 40.

Answer: The angles of the ACD triangle are 40, 50, 90.



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