In triangle ABC, angle A is 50 degrees greater than angle B, and angle C is one-fifth of their sum.
May 3, 2021 | education
| Let the value of the angle ABC = X0, then, by condition, the value of the angle BAC = (50 + X) 0, and the value of the angle ACB = (X + X + 50) / 5 = (2 * X + 50) / 5.
The sum of the interior angles of the triangle is 1800, then:
180 = X + X + 50 + (2 * X + 50) / 5.
180 * 5 = 5 * X + 5 * X + 250 + 2 * X + 50.
12 * X = 600.
X = ABC = 50.
Angle BAC = 50 + 50 = 100.
Angle ACB = (2 * 50 + 50) / 5 = 30.
Answer: The angles of the triangle are 30, 50, 100.
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