In triangle ABC, angle A is 62, angle B is 76. AL, BN and CK bisectors intersecting at point O. Find AOK.

Knowing the values of the two angles of the triangle ABC, we determine its third angle.

Angle ACB = (180 – BAC – ABC) = (180 – 62 – 76) = 42.

Then the angle KCA = AСB / 2 = 42/2 = 21.

In the ACK triangle, the angle AKC = (180 – KAC – KCA) = (180 – 62 – 21) = 97.

Angle KAO = BAC / 2 = 62/2 = 31.

In the AOK triangle, the AOK angle = (180 – KAO – AKO) = (180 – 31 – 97) = 52.

Answer: The AOK angle is 52.



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