In triangle ABC, angle A is 64 degrees, bisectors of angles B and C meet at point D. Find angle CDB.

univerkov | March 9, 2021 | education

The sum of the inner angles of the triangle is 180, then the angle (ABC + ACB) = (180 – BAC) = (180 – 64) = 116.
Since BK and CM are the bisectors of the angles, the sum of the angles (DBC + DСВ) = (АВС + АСВ) / 2 = 116/2 = 58.
Then the angle СDВ = (180 – 58) = 122.
Answer: The CDB angle is 122.

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