In triangle ABC, angle A is 64. The bisectors of angles B and C intersect at point D. Find the CDB angle
| December 16, 2020 | education
Let tr. ABC be isosceles.
1) y.A = y.C = 64 (angles at the base are equal)
y.DCB = 64: 2 = 32 (because the bisector divides the angle in half)
2) y.B = 180- (64 + 64) = 180-128 = 52 (sum of angles tr-s 180)
y.DBC = 52: 2 = 26 (the bisector bisects the angle)
y.CDB = 180- (26 + 52) = 180-78 = 102
Answer: CDB = 102
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