In triangle ABC, angle A is 68 degrees, angle B is 100 degrees. Point K is a continuation of the AC side.

In triangle ABC, angle A is 68 degrees, angle B is 100 degrees. Point K is a continuation of the AC side. Find the angle of the BSC.

Given:
ABC – triangle
∠А = 68 °
∠В = 100 °
Point K is a continuation of the AC side.
To find:
∠ВСК -?

Decision:
In a triangle, the sum of the angles is 180 °
Find C:
C = 180-100-68 = 12 °
∠С is an adjacent angle with VSC, which means that their sum is 180 °
ВСК = 180-12 = 168 °