In triangle ABC, angle A is 75 degrees, angle B is 30 degrees, AB is 10 cm, find the area of the triangle.

Let’s calculate the value of the angle ACB of the triangle.

Angle ACB = (180 – 75 – 30) = 75.

Angle BAC = ACB = 750, then triangle ABC is isosceles and BC = AB = 10 cm.

Let’s define the area of the triangle through the two sides and the angle between them.

Savs = AB * BC * Sin30 / 2 = 10 * 10 * (1/2) / 2 = 100/4 = 25 cm2.

Answer: The area of the triangle is 25 cm2.