In triangle ABC, angle A is straight, AC = 12 cm, cos angle ACB = 0.6. Find the sun.

Let’s build a BBS right-angled triangle with right angle A. Note in the drawing that AC = 12cm. The cosine of the angle is the ratio of the adjacent leg to the hypotenuse. Given the cosine of the angle C, equal to 0.6. Let’s compose the relation:
cosC = AC / BC
6/10 = 12 / BC
BC = 10 × 12/6 = 20cm.
AB = 16,
The answer is 12,16,20-Pythagorean numbers.