In triangle ABC, angle ABC = 50 °, DE belongs to BC, angle BAD = 10 °, angle DAC = 60 °
| April 30, 2021 | education
In triangle ABC, angle ABC = 50 °, DE belongs to BC, angle BAD = 10 °, angle DAC = 60 °, AD = 7 cm. Find the perimeter of triangle ADC.
Determine the value of the angle BAC.
Angle BAC = BAD + DAC = 10 + 60 = 70.
The sum of the inner angles of the triangle is 180, then the angle ABC = (180 – BAC – ABC) = (180 – 70 – 50) = 60.
In triangle ADC, two internal angles are equal to 60, then triangle ADC is equilateral, AC = AD = CD = 7 cm.
Let’s define the perimeter of the ADC triangle.
Rads = 3 * AD = 3 * 7 = 21 cm.
Answer: The perimeter of the ADM triangle is 21 cm.
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