In triangle ABC, angle B = 90, AB = 5cm, BC = 12cm a). Find the distance from point C to straight AB

| May 4, 2021 | education

In triangle ABC, angle B = 90, AB = 5cm, BC = 12cm a). Find the distance from point C to straight AB b). Find the distance between straight BC and the straight line passing through point A parallel to BC.

By the condition of the problem, the angle B is equal to 90 degrees in the triangle ABC. This means that the triangle is rectangular with legs AB and BC. The legs are perpendicular to each other.

The shortest distance from point C to straight line AB is the perpendicular or, in our case, the leg BC. And according to the condition of the problem BC = 12 cm.This means that the distance from point C to line AB is 12 cm.

Let’s draw straight line AO through point A, parallel to line BC.

АО // ВС. If BC is perpendicular to AB, then AO is perpendicular to AB.

AB = 5 cm. The distance between two parallel straight lines AO and BC is 5 cm.



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