In triangle ABC, angle B is 150 degrees, angle A is 45 degrees. Find the radius of the circle described about the triangle if AB = 10.
Determine the value of the angle ACB. Angle ACB = (180 – ABC – BAC) = (180 – 105 – 45) = 30.
Then the radius of the circumscribed circle is:
R = AB / 2 * Sin30 = 10/2 * (1/2) = 10 cm.
Answer: The radius of the circumscribed circle is 10 cm.
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