In triangle ABC, angle B is 20 °, and angle A is twice the angle B. Find angles A and C.

If the angle B is 20 °, and the angle A is 2 times larger, then it is = 40 ° (20 × 2). The angles of any triangle add up to 180 degrees. Let’s find the angle C: 180- (20 + 40) = 120 °.
Answer: angle A = 40 °, angle C = 120 °.



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