In triangle ABC, angle B is 46, angle C = 71, BD is the bisector. Find the angle ADB

Find angle A as the difference between 180 ° (the sum of the angles of the triangle) and the sum of the angles B and C.

A = 180 ° – (71 ° + 46 °) = 180 ° – 117 ° = 63 °.

Let us find the value of the angle ABD as half of the angle B, since the bisector divides it in half by definition.

ABD = 46 °: 2 = 23 °.

Let’s find the ADB angle in the same way as the angle A was calculated.

ADB = 180 ° – (63 ° + 23 °) = 180 ° – 86 ° = 94 °.

Answer: ADB = 94 °.