In triangle ABC, angle B is 64 degrees, angle C is 69 degrees, BD is the bisector. Find the corner ADB.

Since BD is the bisector of the angle ABC, then the angle ABD = ABC / 2 = 69/2 = 34.5. In triangle ABD, angle ADB = (180 – DAB – ABD) = (180 – 64 – 34.5) = 81.5.
Answer: The value of the ADB angle is 81.5.



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