In triangle ABC, angle B is equal to 115, AD is the bisector of angle A, angle C is seven times less

In triangle ABC, angle B is equal to 115, AD is the bisector of angle A, angle C is seven times less than angle ABD. Find the degree measure of the angle C.

Apparently in the condition there is a typo, and instead of the angle ABD we mean the angle ADB.
Consider a triangle ABD, in it we denote the angle A = x, then the angle D = 180 – 115 – x = 65 – x.
The next step is to consider the triangle ABC, in it A = 2x, angle C = 180 – 115 – 2x = 65 – 2x.
According to the condition, it is said that the angle C is seven times less than the angle ADB, we will make the equation:
7 * (65 – 2x) = 65 – x
455 – 14x = 65 – x
13x = 390
x = 30
Find the degree measure of the angle C:
Angle C = 65 – 2x = 65 – 2 * 30 = 65 – 60 = 5 °.
Answer: angle C is 5 °.