In triangle ABC, angle B is right. From the vertex of angle C, a bisector CC1 = 16 is drawn so that BC1 = 8. Find the length AB.

t to BC1 is two times less than the side of CC1, then t to opposite an angle of 30 degrees lies a leg equal to half of the hypotenuse, which means the angle ACB = 3 * 30 = 60 degrees. means the angle CAB = 90-60 = 30 degrees. Opposite an angle of 30 degrees B lies a leg equal to half of the hypotenuse, which means CB = 2AC. By m Pythagoras from tr-ka BCC1 we find BC: BC = root of 192. Then CA = 2√192. Then by T Pythagoras we will find the third. side: AB = √ ((2√ 192) 2-192 * 192) = √ (4 * 192-192) = √576 = 24
Answer: 24