In triangle ABC, angle B is straight. Angle A is 56 degrees greater than angle C. Find the corners of the triangle.

Consider a triangle ABC. According to the problem, the angle B of the straight line is B = 90 °.

If angle A is 56 degrees greater than angle C, then

A = C + 56 °.

But the sum of all the angles of the triangle is 180 °. Then

A + B + C = 180 °,

C + 56 ° + 90 ° + C = 180 °,

2 * C = 34 °,

C = 17 °.

Then the angles of the triangle are:

A = C + 56 ° = 17 ° + 56 ° = 73 °, B = 90 ° and C = 17 °.

Answer: triangle angles 73 °, 90 °, 17 °