In triangle ABC, angle B is straight; N is the point of intersection of the bisectors of angles A and C.

In triangle ABC, angle B is straight; N is the point of intersection of the bisectors of angles A and C. Define the ANC angle.

Since triangle ABC is rectangular, the sum of its acute angles is 90.

Angle (BAC + BCA) = 90.

Since AM and CК are bisectors of the angles, then the angle НAС = BAC / 2, the angle НСA = BCA / 2.

Then the sum of the angles (НAС + НСA) = (BAC + BCA) / 2 = 90/2 = 45.

The sum of the interior angles of the AНС triangle is 180.

Then the angle AНС = 180 – 45 = 135.

Answer: The AНС angle is 135.



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