In triangle ABC, angle B is twice the angle C, angle A is three times the angle C. What are the angles?

Let us express the angle C, for which we use the variable a.
Therefore, according to the condition of the problem, we can write the angle B in the form 2a, while the third angle of this triangle can be expressed through 3a.
Since we know from the school curriculum that the sum of all these angles is 180 °, then we can write down the equation and find what all these angles will be equal to:
3a + a + 2a = 180;
6a = 180;
a = 30;
2 * 30 = 60;
3 * 30 = 90.
Answer: Angle C is 30 °, angle B is 60 ° and angle A is 90 °.