In triangle ABC, angle C = 30 degrees, AC = 10 cm, BC = 8 cm, a straight line a is drawn through vertex a parallel to BC
| January 7, 2021 | education
In triangle ABC, angle C = 30 degrees, AC = 10 cm, BC = 8 cm, a straight line a is drawn through vertex a parallel to BC, find: a) the distance from point B to straight AC b) the distance between straight lines a and BC
The distance from point B to straight line AC is the height BH drawn to the side of the AC, then, in a right-angled triangle BCH, the BH leg is located opposite angle 30, then BH = BC / 2 = 8/2 = 4 cm.
The distance between the straight lines AK and BC is the perpendicular AM, drawn from point a to the straight line BC. Then, in a right-angled AFM triangle, the AM leg is located opposite an angle of 300, then AM = AC / 2 = 10/2 = 5 cm.
Answer: From point B to AC 4 cm, between straight BC and AK 5 cm.
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