In triangle ABC, angle C = 60 °, angle B = 90 °, height BB1 = 2cm. Find AB.

Since triangle ABC is rectangular, angle B = 90, the sum of its acute angles is 90.

Angle (BAC + BAC) = 90.

Angle BAC = 90 – BCA = 90 – 60 = 30.

Segment BB1 is the height of triangle ABC, then triangle BB1A is rectangular.

Leg BB1 of triangle BB1A lies opposite angle 30, then its length is equal to half the length of hypotenuse AB.

BB1 = AB / 2.

AB = 2 * BB1 = 2 * 2 = 4 cm.

Answer: The length of the segment AB is 4 cm.



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