In triangle ABC, angle C = 60 degrees, angle B = 90 height, BB1 = 2 cm, find AB.

In triangle ABC we find the second acute angle A.
Angle A = 90 ° – 60 ° = 30 °.
Consider a triangle AB1B – rectangular (BB1 – height). In this triangle, we know: the angle A = 30 ° and the leg, lying opposite the angle of 30 °, BB1 = 2 cm. The property of this leg is that it is equal to half of the hypotenuse AB. Find AB:
AB = 2 * BB1 = 2 * 2 = 4 cm.
Answer: side AB is 4 centimeters.



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