In triangle ABC, angle C = 60, outside angle CAD = 130 find the outside angle KBC.

Given – in a triangle, the inner angle is <C = 60. The outer angle for angle A (<CAB) is the angle <CAD = 130, so the inner angle with it is <CAB = 180 – 130 = 50.
We need to determine the outer angle <KBC = <BAC + <BCA = 60 + 50 = 110 (degrees)
We determined the value of the outer angle by the sum of two inner angles that are not adjacent to it.



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