In triangle ABC, angle C = 90 ВС = 8 cosA = √21 / 5 Find AB

Let’s define SinA.

Sin2A = 1 – Cos2A = 1 – 21/25 = 4/25.

SinA = 2/5 = BC / AB.

AB = 5 * BC / 2 = 5 * 8/2 = 20 cm.

Answer: The length of the hypotenuse AB is 20 cm.



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