In triangle ABC, angle C = 90, AB = 20, BC = 16. Find sin A.

In triangle ABC, angle C = 90 °, AB = 20, BC = 16.

Find sin A.

In order to find the sin a of the triangle ABC, we use the formula:

sin a = BC / AB (ratio of the opposite leg to the hypotenuse);

Substitute the known values into the formula and find the sine of the angle a.

sin a = 16/20 = 4/5 = 0.8.

Answer: sin a = 0.8.



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