In triangle ABC, angle C = 90 CD-height CD = 4 cm AC = 8 cm, find the angle CAB.

univerkov | July 19, 2021 | education

Since in the ABC triangle the segment CD is its height, the ACD triangle is also rectangular.

In a right-angled triangle, the ratio of the opposite leg to the hypotenuse is the sine of an acute angle.

Then SinCAD = CD / AC = 4/8 = 1/2.

Angle CAD = arcsin (1/2) = 30.

Answer: The value of the angle BAC is 30.

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