In triangle ABC, angle C = 90 ° cos A = 0.28 find sin B.

The cosine of an acute angle of a right-angled triangle is the ratio of the adjacent leg to the hypotenuse.

CosA = AC / AB = 0.28.

The sine of an acute angle of a right-angled triangle is the ratio of the opposite leg to the hypotenuse.

SinB = AC / AB.

Then the cosine of one acute angle of a triangle is equal to the sine of another acute angle.

Answer: SinB = 0.28.



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