In triangle ABC, angle c = 90, cosA = √2 / 2. Find tgA
| March 1, 2021 | education
Given:
right-angled triangle ABC;
angle C = 90;
cosA = √2 / 2;
Find: tgA -?
Decision:
1) Let’s use the formula
cos ^ 2A + sin ^ 2A = 1;
sin ^ 2A = 1 – cos ^ 2A;
sin ^ 2A = 1 – 2/4
sin ^ 2A = 4/4 – 2/4;
sin ^ 2A = 2/4;
sin A = √2 / 2;
2) tgA = sin A / cosA;
tgA = √ 2/2: √ 2/24
tgA = 1.
Answer: 1
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