In triangle ABC: angle C = 90 degrees, AB = 15, cosB = 3/5, find tgA

Given: triangle ABC, angle C = 90 degrees, AB = 15, cosB = 3/5.

Find: tgA.

Decision:

cosB = 3/5,

CB / AB = 3/5,

15 * 3 = CB * 5,

CB = 15 * 3/5,

CB = 9,

AC = root of 15 ^ 2 – 9 ^ 2 = 12,

tgA = CB / AC = 9/12 = 3/4.

Answer: tgA = 3/4.



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