In triangle ABC, angle C = 90 degrees, AB = 8, BC = 2. Find the sine alpha.

Given:

ABC – right triangle;

Angle C = 90 degrees;

AB = 8;

BC = 2;

Find sin a.

Decision:

In order to find the sin a of triangle ABC, you need to divide the opposite leg by the hypotenuse. We get the formula:

sin A = BC / AB.

Substitute the known values into the formula and find sin a.

sin A = BC / AB = 2/8 = 2 / (2 * 4) = 1 / (1 * 4) = ¼ = 0.25;

As a result, we got that sin a = 0.25.

Answer: sin a = 0.25.