In triangle ABC, angle C = 90 degrees AC = 5, cosA = 5 / √41. Find aircraft.

univerkov | September 28, 2021 | education

Let’s define the tangent of the angle BAC through the cosine of this angle.

tg2BAC = (1 / Cos2BAC) – 1 = (1 / (25/41) – 1 = 41/25 – 1 = 16/25.

tgBAC = 4/5.

Then tgBAC = 4/5 = BC / AC.

BC = 4 * AC / 5 = 4 * 5/5 = 4 cm.

Answer: The length of the BC leg is 4 cm.

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