In triangle ABC, angle C = 90 degrees, angle = 30 degrees, AB = 98√3. Find the height CH.

In a right-angled triangle ABC, the leg BC is located opposite the angle A, the degree measure of which, according to the condition, is 30 °. Therefore:
BC = 1/2 * AB = 98√3 / 2 = 49√3.
By the Pythagorean theorem, we find the leg AC:
AC = √ (AB² – BC²) = √ (28812 – 7203) = √21609 = 147.
Consider a right-angled triangle ACN, the hypotenuse AC = 147 and the angle A = 30 ° are known in it.
The CH leg is located opposite corner A, which means that its length:
CH = 1/2 * AC = 147/2 = 73.5.
Answer: The height CH of the triangle ABC is 73.5.