In triangle ABC, angle C = 90 degrees. BC = 35, AC = 5√51. Find sinA.

To begin with, to find the sine, we need to know the length of the hypotenuse, so we use the Pythagorean theorem: AB ^ 2 = AC ^ 2 + BC ^ 2 = 5 √51 * 5 √51 + 35 * 35 = 1275 + 1225 = 2500. So AB = 50.

The sinus is equal to the ratio of the opposite leg to the hypotenuse, therefore, we write down the ratio of the sides: CB / AB = 35/50.

The ratio is equal to sine, so sin A = 35/50 = 7/10.

Answer: 7/10.



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