In triangle ABC, angle C = 90 degrees, CC1-height = 5cm, BC = 10cm Find the angle CAB.

We know that there is a statement that the side opposite to an angle of 30 degrees is half the length of the hypotenuse of the triangle.

In the triangle BCC1 CB = 10 and CC1 = 5 and it is clear that the angle opposite to the CC1 side is the angle B = 30 °.

Now consider the triangle ABC. If the angle C = 90 °, angle B = 30 ° then it is very easy to find the angle CAB (i.e. angle A).

90 ° + 30 ° = 120 °,

180 ° – 120 ° = 60 ° (angle A).

Answer: CAB angle = 60 °.