In triangle ABC, angle C = 90 degrees. Height CC1 = 5 cm, BC = 10 cm. Find the angle CAB.

Since CC1 is the height of a right-angled triangle, triangle BCC1 is right-angled.

In a right-angled triangle BCC1, the length of the CC1 leg is half the length of the BC hypotenuse, then the angle against the CC1 leg is 30.

Angle CBC1 = 30.

The sum of the acute angles of a right-angled triangle is 90, then the angle CAB = (90 – 30) = 60.

Answer: The CAB angle is 60.



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