In triangle abc, angle c = 90 degrees, tg angle A = 12/35, ac = 35. find BC.

The tangent of an acute angle in a right-angled triangle can be found by dividing the leg opposite to the corner by the adjacent leg. In our case, leg BC will lie opposite corner A, and leg AC will be next to it. It turns out that:

tg ⦟A = BC / AC.

Knowing the tangent and one of the legs, we can find another leg:

12/35 = BC / 35.

Multiplying both sides by 35, we get the following answer:

BC = 12.

Answer: BC = 12.